![]() ![]() The following thermodynamic properties will be calculated:ĭensity, dynamic viscosity, kinematic viscosity, specific enthalpy, specific entropy, specific isobar heat capacity cp, thermic conductivity, coefficient of thermal expansion, heat conductance, thermal diffusivity, Prandtl-number, coefficient of compressibility Z, speed of sound.Ĭalculation of tetrafluorethane : if you found an error, please mail to: No garanty for correctness. Lower limit for calculation: -90 C, 0.015 bar bar upper limit: 100 C, 39 bar. The following thermodynamic properties will be calculated: density, dynamic viscosity, kinematic viscosity, specific enthalpy, specific entropy, specific isobar heat capacity cp, thermic conductivity, coefficient of thermal expansion, heat conductance, thermal diffusivity, Prandtl-number, coefficient of compressibility Z, speed of sound. Lower limit for calculation: -70 C, 1 bar upper limit: 180 C, 300 bar.Ĭalculation of thermodynamic state variables of Tetrafluorethan - R134a in saturation state, boiling curve Therefore, the values in the third column represent the amount of heat needed for the heating water from 0.01 oC to a given temperature (at the corresponding pressure).Īs an example, at 95 oC and 84.55 kPa the heat content of water is 397.94 kJ/kg, i.e., we need to supply 397.94 kJ/kg to heat water to the boiling point.įourth column reports the latent heat of evaporation, i.e.,the heat needed to obtain the complete transformation of 1 kg of water into vapor.įor example at 95 ☌ the latent heat of water is 2270.19 kJ/kg.įifth column reports the enthalpy content of vapor which is the sum of enthalpy content of liquid (column 3) and latent heat (column 4).įor example, at 95 ☌ the heat content of steam isģ97.94 kJ/kg + 2270.19 kJ/kg = 2268.13 kJ/kg (column five).Online - Calculation - Tetrafluorethane - R134aĮmail: scientific and engineering data onlineĬalculation of thermodynamic state variables of tetrafluorethane - R134a 23.3.1 Calculate the total heat of 5 kg of steam at an absolute pressure of 8 bar having. ![]() In other words, it is assumed that the enthalpy of water at 0.01 oC is zero. Third column reports the enthalpy content (heat content) of liquid water calculated taking as basis 0.01 oC (the triple point of water). But for the moment we consider them constants in the temperature range considered. Steam can be produced by using energy from fuel or natural gas (a mixture of hydrocarbon gases that occurs with petroleum deposits, principally methane together with varying quantities of ethane, propane, butane, and other gases).Įventually, let's note that latent heat as specific heat depends on pressure and temperature. It is defined as the pressure exerted by a vapor in thermodynamic equilibrium with its condensed phases (solid or liquid) at a given temperature in a closed. In fact, when the vapor is allowed to condense there will be the release of its latent heat of vaporization which can be used for the heating of other substances such as food products. For this reason, steam, the vapor state of water, is largely used as source of heat in many engineering fields. It is interesting to note that most of the energy supplied serves for the evaporation process (about 74%). Therefore, please refer to the demo calculation of Table A-6 for the use of Table A-7 Note: in all the examples above, we take the calculation of internal energy as an demo. Therefore, the enthalpy required to accomplish the process is The use of compressed liquid water table Table A-7 This table shares the similar form as the superheated water table. From these data we can calculate the amount of energy required to accomplish the heating of 1 kg of ice.
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